SUBNETTING CALCULATION

Assume Utem Network is Class B (172.16.0.0)

  1.     Class B subnet default mask is 255.255.0.0 or 11111111.11111111.0.0
  2.     We have 10 faculty and 1 IT Centre, therefore there need to be at least 11 subnets. 2^4 = 16. 4  bits will be borrowed from the host id.
  3.       Mask after subnetting will be 11111111.11111111.11110000.00000000 or 255.255.240.0/20
  4.       Using formula 2^h-2 = 2^4-2 = 14
  5.       Table List of IP Address

Subnet

Network address

Usable address

Broadcast address

0

172.16.0.0/20

172.16.1.0/20 to 172.16.14.0/20

172.16.15.0/20

1

172.16.16.0/20

172.16.17.0/20 to 172.16.30.0/20

172.16.31.0/20

2

172.16.32.0/20

172.16.33.0/20 to 172.16.46.0/20

172.16.47.0/20

3

172.16.48.0/20

172.16.49.0/20 to 172.16.62.0/20

172.16.63.0/20

4

172.16.64.0/20

172.16.65.0/20 to 172.16.78.0/20

172.16.79.0/20

5

172.16.80.0/20

172.16.81.0/20 to 172.16.94.0/20

172.16.95.0/20

6

172.16.96.0/20

172.16.97.0/20 to 172.16.110.0/20

172.16.111.0/20

7

172.16.112.0/20

172.16.113.0/20 to 172.16.126.0/20

172.16.127.0/20

8

172.16.128.0/20

172.16.129.0/20 to 172.16.142.0/20

172.16.143.0/20

9

172.16.144.0/20

172.16.145.0/20 to 172.16.158.0/20

172.16.159.0/20

10

172.16.160.0/20

172.16.161.0/20 to 172.16.174.0/20

172.16.175.0/20

 Therefore, Ulearn System Server address is 172.16.165.0

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